Question

Objects A and B are at the origin. If object A moves to `(6 ,7 )` and object B moves to `(-1 ,3 )` over `4 s`, what is the relative velocity of object B from the perspective of object A?

Answer 1

First, use the Pythagorean Theorem, then use equation `d=vt`

Explanation:

Object A has moved `c=sqrt(6^2+7^2`=9.22m

Object B has moved `c=sqrt((-1)^2+3^2`=3.16m

The velocity of Object A is then `{9.22m}/{4s}=2.31m/s`

The velocity of Object B is then `{3.16m}/{4s}=.79m/s`

Since these objects are moving in opposite directions, these velocities will add, so they will appear to be moving at 3.10 m/s
away from each other.