Question

How do you factor `3b ^ { 2} - 48b + 189`?

Answer 1

`3b^2−48b+189`
taking 3 as a common factor.,

`3(b^2−16b+63 )`
`3(b^2−7b-9b+63 )`
`3(b(b−7)-9(b-7))`
`3(b−9)(b-7)`

Answer 2

`3(b-9)(b-7)`

Explanation:

`"take out a "color(blue)"common factor of 3"`

`rArr3(b^2-16b+63)larrcolor(blue)"factor the quadratic"`

`"the factors of + 63 which sum to - 16 are - 9 and - 7"`

`rArr3(b-9)(b-7)`

`rArr3b^2-48b+189=3(b-9)(b-7)`