Number of real solutions of the equation #log_10(-x) = sqrt(log_10sqrt(x^2))#?

1 Answer
Feb 15, 2018

See below.

Explanation:

#sqrt(x^2) = abs x# then

#log_10 (-x) = sqrt(log_10 absx)# now calling #y = -x#

#log_10 y = sqrt(log_10 abs y)# has sense only for #y= 1# or #y = 10#

then the solutions are for

#x = {-1, -10}#