Find g’(9) where g(x)=(squareroot(x)+3)/(squareroot(x)-1) ?

1 Answer
Feb 16, 2018

3

Explanation:

g(x)=(sqrtx+3)/(sqrtx -1)

Now substitute color(red)(9) for every time you see color(red)x in the expression:

g(color(red)9) = (sqrtcolor(red)9+3)/(sqrtcolor(red)9 -1)

and simplify:

g(9)=(3+3)/(3-1)

g(9)=6/2

g(9)=3