How do you find the unit vector in the direction of the given vector of $v = < 5, - 12 >$ $v=<5,-12>$ ?

Question

How do you find the unit vector in the direction of the given vector of $v = < 5, - 12 >$ $v=<5,-12>$ ?

1 Answer

Impact of this question

59673 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-16T23:20:13

The unit vector of $v = < \frac{5}{13}, - \frac{12}{13} >$ $v=<5/13, -12/13>$ .

Explanation:

Unit vector formula is the vector divided by its magnitude. The formula for magnitude is: given $v = < x, y >, m a g . o f v = \sqrt{x^{2} + y^{2}}$ $v=<x,y>, mag. of v= sqrt(x^2+y^2)$ .
Using the formulas together you get, magnitude of v= $\sqrt{5^{2} + {(- 12)}^{2}} = 13$ $sqrt(5^2+(-12)^2)= 13$ as 5, 12, 13 are a pythagorean triple. Dividing vector v by its magnitude results in: unit vector = $v \cdot \frac{1}{13}$ $v*1/13$ = $< \frac{5}{13}, - \frac{12}{13} >$ $<5/13,-12/13>$ .

Science

Math

Humanities

... and beyond

How do you find the unit vector in the direction of the given vector of $v = < 5, - 12 >$ $v=<5,-12>$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the unit vector in the direction of the given vector of v=<5,−12>v=<5,-12>?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find the unit vector in the direction of the given vector of $v = < 5, - 12 >$ $v=<5,-12>$ ?