What happens to the volume of a gas if the pressure decreases by 5 %?

2 Answers
Feb 17, 2018

5 % increase.

Explanation:

Use

PV = nRT

  • For first case, color(white)(m)PV = nRTcolor(white)(m)bb((1)
  • For second case, pv=nRTcolor(white)(m)bb((2))

Per (1) and (2),

pv = PV

v=(PV)/p = (PV)/(0.95P) = (100V)/95 = 1.05V (105 % of original volume)

"Increase in"color(white)(l) V = "105 % - 100 % = 5 %".

Feb 17, 2018

Consider,

PV = nRT

=> P_1V_1 = nRT = P_2V_2

therefore P_1V_1 = P_2V_2

Moreover, consider in the first case that P = 1, and in the second case P = 1 - 0.05 = 0.95.

Hence,

PV_1 = 0.95PV_2

=> 1.05V_1 = V_2

To be sure, if the pressure is decreased by 5%, ceteris paribus, then the volume will increase by approximately 5%. This is dictated by the inverse relationship mathematically illustrated above.