If secA-tanA=a,show that ; secA=1/2[a+1/a]& tanA=1/2[1/a-a]?

1 Answer
Feb 17, 2018

Please look explanation section.

Explanation:

#secA-tanA=a#

#(secA-tanA)(secA+tanA)=a(secA+tanA)#

#a*(secA+tanA)=(secA)^2-(tanA)^2#

#a*(secA+tanA)=1#

#secA+tanA=1/a#

After solving equations of #secA-tanA=a# and #secA+tanA=1/a# are together,

#secA=1/2*(a+1/a)# and #tanA=1/2*(1/a-a)#