Question

How many grams of solute are needed to prepare each of the following solutions?

1.00 L of 0.165 M NaCl

Answer 1

Recall,

`"M" = (1"mol")/(1"L")`

The first is easy,

`0.165"M" * 1.00"L" = 0.165"mol"`

`0.165"mol" * (58.5g)/"mol" approx 9.65g`

of sodium chloride are required.

The next one we would do some math to make it easier prior to starting:

`2.50 * 10^2"mL" * ("L")/(10^3"mL") * 0.140"M" approx 0.0350"mol"`

`0.0350"mol" * (159.6g)/"mol" approx 5.59g`

of copper sulfate are required.

I left the third for you! Convince yourself you know how to do this and refer to my work if you get lost!