Question

If an unbiased die is thrown, what is the probability that it will show a 3 or an even number?

Answer 1

`2/3`

Explanation:

So, a normal die has 6 sides, unless the question is referring to another type of die (e.g. 8 sided).

In a 6-sided die, there are four numbers that fits the requirements: 2,3,4, and 6. Given that there are 4 possibilities and 6 total outcomes, you just divide those to numbers to get
`4/6 = 2/3`

Answer 2

`2/3` or `~~66.7%`

Explanation:

The possibilities are each of the six sides.

`1, 2, 3, 4, 5, and 6`

What we're interested in is `3` or even, so that's

`2, 3, 4, and 6`

That's four out of the six possible numbers the die can land on, so your answer for probability is

`P = 4/6`

which can be simplified into `2/3` or converted to about `66.7%`.

Answer 3

2/3

Explanation:

Let X=number on the die.
Since the die is unbiased, we can use the classical approach in assigning the probabilities.

`P(X=3)=1/6`

P(X=2 U X=4 U X=6)=`1/6 + 1/6 + 1/6 = 3/6`

Since the problem is an 'or' statement (meaning union) then,

P(X=3 U X=2 U X=4 U X=6) = P(X=3)+P(X=2 U X=4 U X=6) = `1/6+3/6=4/6=2/3`