Question #ce2b1

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Answer 1 · 2018-02-20T06:38:34

See the explanation

A term in a GP is represented by $ar^(n-1)$ .

Here , a is the first term.

$->$ r is the common ratio.

$->$ n is the number of term.

For finding the first four terms calculate $a_2 , a_3 , a_4$

$-> a_1 = 2$

$-> a_2 = 2 times 4^(2-1)$

$" " = 2 times 4$

$" " = 8$

Similarly , $a_3 = 32 and a_4 = 128$

So , the first four terms of the GP are

$2 , 8 , 32 , 128$