How do you graph, find the zeros, intercepts, domain and range of f(x)=13|2x1|?

1 Answer
Feb 20, 2018

domain {x,x(,+)}
range d{y,y[0,+)}

See explanation.

Explanation:

This is of graph type .

The part |2x1| is always positive so 13|2x1| is also always
positive. Thus y0

Determin the vertex

Set y=0=13|2x1|

Multiply both sides by 31

y=0=|2x1|

y=0=|0|

So 2x1=0x=12

So the the vertex of is at (x,y)(12,0)

Thus the vertex is on the x-axis. There is no plot below the x-axis.
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Determine the y-intercept

Set x=0 giving:

y=13|01|

y=13×(+1)=13

yintercept(x,y)=(0,13)
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Plot two graphs but cit them off so that there is no line below the x-axis

Line 1 y=13(2x1) where x0
Line 2 y=13(2x1) where x0

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