If an unbiased die is thrown, what is the probability that it will show a 3 or an even number?

3 Answers
Feb 20, 2018

2/3

Explanation:

So, a normal die has 6 sides, unless the question is referring to another type of die (e.g. 8 sided).

In a 6-sided die, there are four numbers that fits the requirements: 2,3,4, and 6. Given that there are 4 possibilities and 6 total outcomes, you just divide those to numbers to get
4/6 = 2/3

Feb 20, 2018

2/3 or ~~66.7%

Explanation:

The possibilities are each of the six sides.

1, 2, 3, 4, 5, and 6

What we're interested in is 3 or even, so that's

2, 3, 4, and 6

That's four out of the six possible numbers the die can land on, so your answer for probability is

P = 4/6

which can be simplified into 2/3 or converted to about 66.7%.

Feb 20, 2018

2/3

Explanation:

Let X=number on the die.
Since the die is unbiased, we can use the classical approach in assigning the probabilities.

P(X=3)=1/6

P(X=2 U X=4 U X=6)=1/6 + 1/6 + 1/6 = 3/6

Since the problem is an 'or' statement (meaning union) then,

P(X=3 U X=2 U X=4 U X=6) = P(X=3)+P(X=2 U X=4 U X=6) = 1/6+3/6=4/6=2/3