Sketch the graph of $y = sin θ$ $y= sin theta$ for $- π \leq θ \leq π$ $-pi <= theta <=pi$ ?

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Answer 1 · 2018-02-20T15:17:16

See below.

To sketch this we must know 4 common points of the graph.

We know that $π$ $pi$ in radians is $180^{\circ}$ $180^circ$

This means that $\frac{π}{2}$ $pi/2$ is $90^{\circ}$ $90^circ$

From our knowledge, a sine graph has the coordinates:

$(0, 0) (90, 1) (180, 0) (- 90, - 1) (- 180, 0)$ $(0,0) (90,1) (180,0) ( -90, -1) (-180,0)$

Converting these to radians we get:

$(0, 0) (\frac{π}{2}, 1) (π, 0) (- \frac{π}{2}) (- π, 0)$ $(0,0) ( pi/2,1) (pi,0) ( -pi/2) ( -pi,0)$

We know that a sine graph oscillates between $1$ $1$ and $- 1$ $-1$ .

This means we need to label the $y$ $y$ axis with the $1$ $1$ and $- 1$ $-1$ .

Along the $x$ $x$ axis we must go up in radians, use the points mentioned above.

Plot the points on the graph and sketch with a nice smooth curve.

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Notice that the graph repeats this pattern throughout.

Sketch the graph of y=sinθy= sin theta for −π≤θ≤π-pi <= theta <=pi?