Question

Sketch the graph of `y= sin theta` for `-pi <= theta <=pi`?

Answer 1

See below.

Explanation:

To sketch this we must know 4 common points of the graph.

We know that `pi` in radians is `180^circ`

This means that `pi/2` is `90^circ`

From our knowledge, a sine graph has the coordinates:

`(0,0) (90,1) (180,0) ( -90, -1) (-180,0)`

Converting these to radians we get:

`(0,0) ( pi/2,1) (pi,0) ( -pi/2) ( -pi,0)`

We know that a sine graph oscillates between `1` and `-1`.

This means we need to label the `y` axis with the `1` and `-1`.

Along the `x` axis we must go up in radians, use the points mentioned above.

Plot the points on the graph and sketch with a nice smooth curve.

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Notice that the graph repeats this pattern throughout.