Where did i go wrong?

Question

8^(4x-1)=25

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Answer 1 · 2018-02-20T16:13:44

#x~~.637#

#8^(4x-1)=25#

To undo the power of #4x-1# we take the #log_8# of both sides:

#log_8 8^(4x-1)=log_8 25#

=

#4x-1=1.548...#

=

#4x=2.548...#

=

#x~~.637#

Not sure what you got, but I hope this helps.