How to simplify sinΘ cscΘ?

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Answer 1 · 2018-02-20T22:09:08

1

#csc(theta)# is the reciprocal of #sin(theta)#, meaning that #csc(theta)=1/sin(theta)#

#sin(theta) * 1/sin(theta)# = #sin(theta)/sin(theta)=cancel(sin(theta))/cancel(sin(theta))=1#

Answer 2 · 2018-02-20T22:09:30

1

#csctheta# is equivalent to #1/sintheta#

So multiply across:

#sintheta*csctheta#

=

#sintheta/1*1/sintheta#

=

#sintheta/sintheta#

=

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