Question

What is `bar(2).75 + bar(3).78` ?

Answer 1

In `10`-adic arithmetic:

`bar(2).75 + bar(3).78 = bar(5)6.53`

Explanation:

The question does make sense in the context of `10`-adic numbers - which is rather an esoteric context, since `10`-adic numbers are quite poorly behaved.

In that context, we would have:

`bar(2).75 + bar(3).78 = (bar(2)+bar(3)) + (0.75+0.78) = bar(5)+1.53 = bar(5)6.53`

where `bar(2) = -2/9`, `bar(3) = -1/3` and `bar(5) = -5/9`

Answer 2

`bar(2).75+bar(3).78=bar(4).53`

Explanation:

A bar is also used when we use logarithm to the base `10`,

where `bar(2).75` means `-2+.75`, the integral part being characteristic and fractional or decimal part is mantissa.

and `bar(3).78` is `-3+.78`

Hence `bar(2).75+bar(3).78`

= `-2+0.75-3+0.78`

= `-5+1.53`

= `-4+0.53`

= `bar(4).53`