A rectangular room is 5 meters longer than it is wide,and it's perimeter is 26 meters. What isthe dimension of the room?

2 Answers
Feb 21, 2018

The room is 4 feet wide and 9 feet long.

Explanation:

The best way to solve word problems like this is to create an equation.

The room is five meters longer than its width. If the width is represented by x, then the length has to be x + 5.

Now, how many sides does a rectangle have? 4. 2 of these sides are the width of the rectangle and the other 2 sides are the length of the rectangle, whose combined total length, the perimeter, is equal to 26 meters.

x + x + (x+5) + (x+5)=26

4x+10=26

4x=16

x=4

We are told that the room is longer than it is side, so the width is 4 meters, and the length is x+5 meters long. The length is 9 meters.

Feb 21, 2018

"length "=9" m and width "=4" m"

Explanation:

"let the width of the room "=w

"then the length "=w+5larrcolor(blue)"5 m lomger than width"

• " perimeter "=(2xx"length")+(2xx"width")

rArr"perimeter "=2w+2(w+5)

color(white)(rArr"perimeter ")=2w+2w+10=4w+10

"now perimeter "=26

rArr4w+10=26

"subtract 10 from both sides"

4wcancel(+10)cancel(-10)=26-10

rArr4w=16

"divide both sides by 4"

(cancel(4) w)/cancel(4)=16/4

rArrw=4

"width "=w=4" m"

"length "=w+5=4+5=9" m"