Question

How do you determine the quadrant in which `-(11pi)/9` lies?

Answer 1

The negative means you go clockwise instead of counterclockwise to graph the angle. Then...

Explanation:

Then, since `11/9` is a little more than one, it means the angle is a little more than `\pi` (or 180 degrees). Therefore, when you graph an angle moving clockwise and go past `\pi` radians, you will be in Quadrant II

Answer 2

Second quadrant.

Explanation:

`-(11pi)/9 = -1((2pi)/9) = -pi - ((2pi)/9)`

`=> 2pi - pi - ((2pi)/9) = (7pi)/9`

Since `(7pi)/9 > pi/2`, it is in second quadrant.

Aliter : -(11pi)/9 = -((11pi)/9) * (360/2pi) = - 220^@#

`=> 360 - 220 = 140^@ = (90 + 50)^@`

It’s in second quadrant, as `140^@` is between `90^@` and `180^@`