Question #65a5e

1 Answer
Feb 22, 2018

lim x-(tanx/t^2) =0
x->0

Explanation:

I'm not exactly sure where t comes from, but it cancels out in the end anyway

x->0; x-(tanx/t^2)
(0)-(tan(0)/t^2)
0-((0/1)/t^2)
0-(0/t^2)
0-(0)
0

If you have a value for t, you can graph it and find the limit that way. This graph is if t=0. Regardless, (0,0) is always constant.
graph{x-tanx [-25.83, 25.16, -12.34, 13.1]}