Question #65a5e

1 Answer
Feb 22, 2018

lim #x-(tanx/t^2)# #=0#
#x->0#

Explanation:

I'm not exactly sure where #t# comes from, but it cancels out in the end anyway

#x->0; x-(tanx/t^2)#
#(0)-(tan(0)/t^2)#
#0-((0/1)/t^2)#
#0-(0/t^2)#
#0-(0)#
#0#

If you have a value for #t#, you can graph it and find the limit that way. This graph is if #t=0#. Regardless, (0,0) is always constant.
graph{x-tanx [-25.83, 25.16, -12.34, 13.1]}