Question

If 2s1 given how to find n,l,ml?

Answer 1

Please refer to the explanation below.

Explanation:

We got the orbital occupation `2s^1`.

Recall that, `n` is the principal shell of the atom, `l` is the orbital angular momentum quantum number, and `m_l` is the magnetic quantum number. But, knowing their conditions will be more important here.

`n` can be any natural number `(1,2,3,...)`

`l` depends on `n`, but it ranges from `0<=l<=n-1`, i.e. `l` can anything between `(0,1,2,3,...,n-1)`.

`m_l` depends on `l`, and it ranges from `-l<=m_l<=l`, i.e. it can be anything between `(-l,-l+1,-l+2,...,-1,0,1,2,...,l-2,l-1,l)`.

Here, the `2s^1` orbital occupation is within the second shell, so we got:

`n=2`

Since `n=2` and we have an `s` orbital, then `l` can only be `0`.

`n=2, l=0`, then `m_l` can only "range" from `0` to `0`.