An object with a mass of $4 k g$ $4 kg$ is moving at $7 \frac{m}{s}$ $7 m/s$ over a surface with a kinetic friction coefficient of $1$ $1$ . How much power will it take to accelerate the object at #4 m/s^2?

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An object with a mass of $4 k g$ $4 kg$ is moving at $7 \frac{m}{s}$ $7 m/s$ over a surface with a kinetic friction coefficient of $1$ $1$ . How much power will it take to accelerate the object at #4 m/s^2?

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Answer 1 · 2018-02-23T07:00:08

386 W

Explanation:

The force you must give, must equilibrate both the inertia force and the friction force:
$F_{t} = F_{i} + F_{f} = m \times a + m \times g \times μ_{f} = 4 k g \times 4 \frac{m}{s^{2}} + 4 k g \times 9.8 \frac{m}{s^{2}} \times 1 = 16 N + 39.2 N = 55.2 N$ $F_t= F_i+ F_f= mxxa + m xx g xx mu_f= 4 kg xx 4 m/ s^2+ 4kg xx 9.8 m/s^2 xx 1= 16 N + 39.2 N = 55.2 N$
The power is given by :
$P = F_{t} \times v = 56 N \times 7 \frac{m}{s} = 386 W$ $P= F_t xx v= 56 N xx 7 m/s = 386 W$
Because the few significative figures used it has no sense a bigger precision

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An object with a mass of $4 k g$ $4 kg$ is moving at $7 \frac{m}{s}$ $7 m/s$ over a surface with a kinetic friction coefficient of $1$ $1$ . How much power will it take to accelerate the object at #4 m/s^2?

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An object with a mass of $4 k g$ $4 kg$ is moving at $7 \frac{m}{s}$ $7 m/s$ over a surface with a kinetic friction coefficient of $1$ $1$ . How much power will it take to accelerate the object at #4 m/s^2?