A 0.176 mol sample of Kr gas is contained in a 8.00 L flask at room temperature and pressure. What is the density of the gas, in grams/liter, under these conditions?

1 Answer
1s2s2p · Surya K.
Feb 23, 2018

#rho=1.84gcolor(white)(l)L^-1#

Explanation:

First, we need to find the mass of #"Kr"# by using the equation:

#m/M_r=n#, where:

  • #m# = mass (#g#)
  • #M_r# = molar mass (#gcolor(white)(l)mol^-1#)
  • #n# = number of moles (#mol#)

#m=nM_r#

#m("Kr")=n("Kr")M_r("Kr")=0.176*83.8=14.7488g#

#rho=m/V=14.7488/8=1.8436~~1.84gcolor(white)(l)L^-1#

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