Question

What is the balance equation of potassium nitrate(KNO3) TO SUGAR (C12H22O11)?

WHAT IS THE SOLUTION TO THE ANSWER
(48KNO3+5C12 H22 O11=36CO2+24K2CO3+24N2)?

Answer 1

So you are oxidizing sugar to carbon dioxide?

Explanation:

Well, as per standard, we use separate redox equations....

The carbon in sugar is OXIDIZED to `CO_2`...

`stackrel(0)C_6stackrel(+I)H_12stackrel(-II)O_6 +6H_2Orarr 6stackrel(+IV)CO_2+24H^+ +24e^(-)` `(i)`

And nitrate `N(+V)` is reduced to dinitrogen, i.e. `N(0)`...

`NO_3^(-)+6H^+ +5e^(-) rarr 1/2N_2 + 3H_2O` `(ii)`

And so `5xx(i)+24xx(ii)`

`5C_6H_12O_6 +24NO_3^(-)+144H^+ +120e^(-)+30H_2Orarr 30CO_2+120H^++12N_2 + 72H_2O +120e^(-)`

And we cancel common reagents...

`5C_6H_12O_6 +24NO_3^(-)+24H^+ rarr 30CO_2+12N_2 + 42H_2O`

`"..arithmetic...whew"`..and this is I think balanced with respect to mass and charge...