A rigid container of O2 has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273 K if the volume and number of moles has not changed?

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Answer 1 · 2018-02-26T16:23:48

#130.2"kPa"#

According to Gay-Lussac's Law:

#PpropT#.

It follows that #P=kT#, and so:

#P/T=k#. It means that we can also say:

#P_1/T_1=P_2/T_2#

We need to find #P_2#. Rearranging to solve for such:

#P_2=(P_1T_2)/T_1#

We know that:

#P_1=340"kPa"#

#T_1=713"K"#

#T_2=273"K"#

Inputting:

#P_2=(340*273)/713#

#P_2=130.2"kPa"# is the new pressure.