Calculate the heat absorbed by 15 g of water to raise its temperature from #20^oC# to #50^oC# (at constant pressure)? The specific heat of water is #4.18J(g^oC)#.

1 Answer
Surya K.
Feb 27, 2018

#1881"J"# of heat must be absorbed.

Explanation:

The energy, #q#, needed to increase the temperature of an object of mass #m#, by a temperature #theta#, where the substance's specific heat is #c#, is given by:

#q=mctheta#

Here,

#m=15"g"#

#c=4.18"J/(g"^@"C)"#

#theta=50-20=30^@"C"#

Inputting:

#q=15*4.18*30#

#q=1881"J"#

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