Question

A dice is rolled, what is the probability of getting 1 and 6?

A. 1/6
B. 2/36
C. 1/36
D. 3/6

Answer 1

`2/36`

Explanation:

I assume that dice has been rolled twice. So, there could be 1 number on the top side each time.
I also assume that the numbers may or may not appear in given sequence.

probability of getting `1` or `6` first time `=2/6`

Now since we have got either of six or one we need the other one now.

Examples are better for explaining. So, consider that 1 appeared on top now we need 6.
So probability of getting `6" is "1/6`.
Multiply both probabilities and we get `2/6×1/6=2/36`
(note we could have got 6 also first time but that doesn't hinder our calculation)

Answer 2

If we ask "What is the probability of rolling a 1 and then rolling a 6?", the answer is C `=1/36`

Explanation:

I'm going to run through what we're given and see if we can piece this together.

When we roll a single die, we're only going to get a single roll - we can't get both a 1 and a 6, which is what the question currently asks.

So what if we ask the question - What is the probability of rolling a 1 and then rolling a 6?

With this question, we have an answer that makes sense.

The probability of rolling a 1 is `1/6`. On the next roll, the probability of rolling a 6 is also `1/6`. Since these are independent events, we multiply to see the probability of rolling a 1 and then rolling a 6:

`1/6xx1/6=1/36`

If we ask the question What is the probability of rolling a 1 or a 6, we look at the number of ways we can meet the conditions `(=2)` over the number of ways a die can come up `(=6)`, and get:

`2/6` - but there is no option for this and so probably isn't the question being asked.