What is the y-intercept of 2x-5y =35?

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Answer 1 · 2018-03-02T03:39:21

#(0,-7)#

To find the #y#-intercept of an equation, set #x# equal to #0# and solve:

In the case of #2x-5y=35,# let's replace all instances of #x# in the equation with #0# and solve for #y:#

#2(0)-5y=35#

#-5y=35#

#(cancel(-5)y)/(cancel(-5))=35/-5#

#y=-7#

Thus, the #y#-intercept is at #(x,y)=# #(0,-7).#