How do you simplify #(sqrt5 + sqrt2) (sqrt5 - sqrt2)#?

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Answer 1 · 2018-03-02T15:44:00

#3#

A math rule states that:

#(a+b)(a-b)=a^2-b^2#

Here, #a=sqrt5#
Here, #b=sqrt2#

Substituting the values:

#(sqrt5+sqrt2)(sqrt5-sqrt2) = (sqrt5)^2-(sqrt2)^2#

Cancelling out:

#->(5)-(2)#

#=5-2#

#=3#

Thus, solved