Question

How do you solve `y=2x^2-4x-48` by factoring?

Answer 1

`y=2(x+4)(x-6)`
is the factored form of
`y=2x^2-4x-48`

Explanation:

`y=2x^2-4x-48`
Now,
Dividing the equation by 2
`1/2y=1/2(2x^2-4x-48)`
`1/2y=x^2-2x-24`
`x^2-2x-24=x^2+4x-6x-24`
`=(x^2+4x)-(6x+24)`

`1/2y=x(x+4)-6(x+4)`
`1/2y=(x+4)(x-6)`
`y=2(x+4)(x-6)`
is the factored form of
`y=2x^2-4x-48`