What is the distance between #(3 ,(7 pi)/6 )# and #(-2 , (5 pi )/12 )#?

1 Answer
Mar 3, 2018

#sqrt((4900 + (81pi^2))/196)# units

Explanation:

let (#x_1,y_1#)= (3, #7pi#/6) and (#x_2,y_2#)= (-2, #5pi#/12)
Now using the distance formula,
distance = #sqrt((x_2-x_1)^2 + (y_2-y_1)^2)#
= #sqrt((-2-3)^2 + (5pi/12-7pi/6)^2)#
=#sqrt((-5)^2 + ((5pi-14pi)/14)^2#
= #sqrt(25 + ((-9pi)/14)^2#
= #sqrt(25 + (81pi^2)/196)#
= #sqrt((4900 + (81pi^2))/196)# units
you can put the value of #pi# as 22/7 and use the calculator to find the distance.