What is the value of #6x^2+17# when #x=8#?

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Answer 1 · 2018-03-03T08:22:34

#401#

We have the function #6x^2+17#

Simply input #x=8# into it:

#6*(8)^2+17#

#6*64+17#

#401#

Answer 2 · 2018-03-03T08:24:58

#color(red)(=401)#

#6x^2+17#

[Replacing x=8]

#=6xx(8)^2+17#

#=6xx64+17#

#=384+17#

#color(red)(=401)#

~Hope this helps! :)

Answer 3 · 2018-03-03T08:27:20

#401#

#"to evaluate substitute "x=8" into the expression"#

#rArr(6xx(color(red)(8))^2)+17#

#=(6xx64)+17#

#=384+17=401#