How do you simplify #sqrt(b^4c^5)#?

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Answer 1 · 2018-03-02T23:35:05

#b^2c^(5/2)#

Recall that #sqrt(x)=x^(1/2).#

Therefore,

#sqrt(b^4c^5)=(b^4c^5)^(1/2)#

Recall that #(xy)^z=x^zy^z#.

Therefore,

#(b^4c^5)^(1/2)=b^(4*1/2)*c^(5*1/2)=b^2c^(5/2)#

Answer 2 · 2018-03-03T14:15:29

#sqrt(b^4 c^5# simplifies to #b^2 c^2# #sqrtc#

Simplify #sqrt(b^4 c^5#

1) Factor into perfect squares as far as possible

#sqrt((b^2)^2 (c^2)^2 (c)#

2) Find the square roots of the perfect squares, but leave the others inside

#b^2 c^2# #sqrt(c)# #larr# answer