If x varies inversely with y and x = 8 when y = 6, how do you find y when x = 1?

1 Answer
Mar 3, 2018

y=48y=48

Explanation:

xx is inversely proportionate to yy can be written as:

xprop1/yx1y -> x=k/yx=ky

Where kk is just an ungiven value that we need to figure out..

Inputting values given:

8=k/68=k6

therefore k=8xx6=48

This is therefore written as:

x=48/y

Therefore when y=1, using our little formula for this...

1=48/y

Multiplying by y solves this as it would cancel out the divide, giving us:

y=48