How do you find the amplitude and period of #y= 3 sin 2pix#?

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Answer 1 · 2018-03-04T01:53:43

Amplitude 3, Period 1

Standard form of sine function

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#

Given : #y = 3 sin (2pix) #

#a = 3, b = 2pi#

Amplitude # = a = 3#

Period # = (2pi)/ |b| =( 2pi) / (2pi) = 1#

graph{3sin(2pix) [-10, 10, -5, 5]}