How do you find the slope of (-1, -5) and (-4, -5)?

2 Answers
Mar 4, 2018

See a solution process below:

Explanation:

The slope can be found by using the formula: #m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))#

Where #m# is the slope and (#color(blue)(x_1, y_1)#) and (#color(red)(x_2, y_2)#) are the two points on the line.

Substituting the values from the points in the problem gives:

#m = (color(red)(-5) - color(blue)(-5))/(color(red)(-4) - color(blue)(-1)) = (color(red)(-5) + color(blue)(5))/(color(red)(-4) + color(blue)(1)) = 0/-3 = 0#

A line with a slope of #0# is, by definition, a horizontal line.

This can be seen in this problem because the #y# value for both points are the same: #-5#

Mar 4, 2018

#m=0#

Explanation:

If line passing through two different points #A(x_1,y_1)andB(x_2,y_2), then#,slop of #l# is
#color(red)(m=(y_2-y_1)/(x_2-x_1))#,where,#x_1!=x_2#.
Here,#A(-1,-5),andB(-4,-5)#
#m=((-5)-(-5))/((-4)-(-1))=0/-3=0#
Note: #y_1=y_2rArrl# ,is passing through y=-5,and #l# is // to #X-#axis.So, the slop of #l,is# .0