How do you factor the expression $x^{2} - 6 x + 5$ $x^2 - 6x + 5$ ?

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How do you factor the expression $x^{2} - 6 x + 5$ $x^2 - 6x + 5$ ?

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Answer 1 · 2018-03-04T19:29:37

$(x - 5) (x - 1)$ $(x-5)(x-1)$

Explanation:

The corresponding equation is $x^{2} - 6 x + 5 = 0$ $x^2-6x+5=0$
$D = 36 - 20$ $D=36-20$
$D = 16$ $D=16$

$x_{1} = \frac{6 + \sqrt{16}}{2} = \frac{10}{2} = 5$ $x_1=(6+sqrt(16))/2=10/2=5$
$x_{2} = \frac{6 - \sqrt{16}}{2} = \frac{2}{2} = 1$ $x_2=(6-sqrt(16))/2=2/2=1$

So the expression becomes: $(x - 5) (x - 1)$ $(x-5)(x-1)$

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How do you factor the expression $x^{2} - 6 x + 5$ $x^2 - 6x + 5$ ?

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How do you factor the expression $x^{2} - 6 x + 5$ $x^2 - 6x + 5$ ?