How do you solve the system of equations #x+ y = - 4# and #- 8x + 3y = 21#?

1 Answer
Mar 4, 2018

x=-3 and y=-1

Explanation:

We have, #x +y=-4#
or,#y=-4-x#
Multiplying both sides with 3,we have,
#3y=-12-3x#
Substituting the value of #3y# in the equation #3y-8x=21#,we get,
#-12-3x=21+8x#
Or,#-33=11x#
Thus,#x=-3#
Putting the value of #x# in first equation,we get #y# as #-4-(-3)# or #y=-1#