How do I factor; x^2-15x+56=?

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Answer 1 · 2018-03-05T01:37:56

#x^2-7x-8x+56=?#

For #x^2-15x+56#

it is gonna be like this:

#x^2-7x-8x+56#

#=x(x-7)-8(x-7)#

#=(x-7)(x-8)#

Then if

#x^2-15x+56 = 0#

#(x-7)(x-8)= 0#

So

#x-7=0 => x=7#

#x-8=0 => x=8#