How do you solve the system of equations #2a-4b=6# and #a+3b=-7#?

1 Answer
Juliana
Mar 5, 2018

#a=-1#, #b=-2#

Explanation:

Multiplying the second equation by 2, we have #2a+6b=-14#. Subtracting this equation into the first equation that was given in the problem #=># #10b=-20# => #b=-2#.
We now know #b=-2#, solving for #a# should be easy. Plug #b=-2# into any one of the equation, and then solve for #a# #=># #a+3(-2)=-7# #=># #a-6=-7# #=># #a=-1#

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