How do you foil #(2x+4)(x+3)#?

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Answer 1 · 2018-03-05T07:03:17

#2x^2 + 10x + 12#

I use a method similar to multiplication; distribute first the #x# and then the three.

#(2x + 4)#
#(x + 3)#

#2x^2 + 4x#

#" " " " +6x + 12#

Answer 2 · 2018-03-05T07:05:57

#(2x + 4)(x + 3) = 2x^2 + 10x + 12#

Expand the following binomial product:

#(2x + 4)(x + 3)#

First: #2x xx x#

Outside: #2x xx 3#

Inside: #4 xx x#

Last: #4 xx 3#

Now we can combine them by adding them together.

#2x xx x + 2x xx 3 + 4 xx x + 4 xx 3#

We can simplify from there.

#2x^2 + 6x + 4x + 12#

#2x^2 + 10x + 12#

Because there are no common factors here, we can not simplify it any further.