How do you graph 4x+y=0?

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Answer 1 · 2018-03-05T15:26:11

graph{y=-4x [-10, 10, -5, 5]}

To solve this equation, first move the #4x# to the other side to make the #y# by itself. Do this by subtracting #4x# from each side.

#y+4x-4x=0-4x #

Simplify

#y=-4x#

Once you simplify, plug in random values for #x# #(1, 2, 3, "etc")# and then the answer you get is your #y# value. You can use the graph for help.

Example:

#x = 2 => y=-4(2) =-8#

So

#x = 2, y = -8#

Answer 2 · 2018-03-05T15:31:18

See explanation.

#4x+y=0#
#y=-4x#

Since the equation has the form of #y=ax#, we conclude that the graph will be a straight line passing through the #(0,0)# point.

You then insert #2# values for #x# #(x_1,x_2)# and get #2# values for #y# #(y_1,y_2)#.

So you have #2# coordinates: #(x_1,y_1)# and #(x_2,y_2)#.

You mark them as points and draw a straight line that passes through both points and the #(0,0)# point.

graph{y=-4x [-10, 10, -5, 5]}