A bag contains 5 blue marbles, 6 red marbles, and 9 green marbles. Two marbles are drawn at random. What is the probability of first drawing a blue marble and then, without replacing it, drawing a red marble?

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Answer 1 · 2018-03-05T16:21:12

$color(red)(=3/38$

Probability = no. of favourable outcomes /total no. of outcomes

Probability of getting a blue marble $=5/(5+6+9)=color (Magenta)(5/20$

Probability of getting a red marble $=6/(20-1)=$ $color (Magenta)(6/19$

$5/20xx6/19$

$color(red)(=3/38$

~Hope this helps! :)