Question

A bag contains 5 blue marbles, 6 red marbles, and 9 green marbles. Two marbles are drawn at random. What is the probability of first drawing a blue marble and then, without replacing it, drawing a red marble?

Answer 1

`color(red)(=3/38`

Explanation:

Probability = no. of favourable outcomes /total no. of outcomes

Probability of getting a blue marble`=5/(5+6+9)=color (Magenta)(5/20`

Probability of getting a red marble`=6/(20-1)=` `color (Magenta)(6/19`

`5/20xx6/19`

`color(red)(=3/38`

~Hope this helps! :)