How do you simplify the square root #sqrt49#?

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Answer 1 · 2018-03-06T01:41:11

#sqrt49=sqrt((pm7)^2)=pm7#

If I have a number, say 7, and I square it, I'll get #7^2=49#

The square root is the opposite of the square operation. And so when we take the square root of a number that is squared, the two operations cancel:

#sqrt49=sqrt(7^2)=7#

Keep in mind that if I were to square #-7#, I'd end up with the same starting place:

#(-7)^2=49#

Which one is the answer to #sqrt49#? #7# or #-7#? We don't know. And so we list out both possible answers:

#sqrt49=sqrt((pm7)^2)=pm7#