Sec^2x+tan^2xsec^2x=sec^4x?
1 Answer
Mar 6, 2018
See below...
Explanation:
#sec^2x+tan^2x cdot sec^2x#
#=sec^2x(1+tan^2x)#
#=sec^2x cdot sec^2x#
#=sec^4x" "# [as#color(red)(sec^2theta=1+tan^2theta# ]
Hope it helps...
Thank you...