How do you solve #\frac{2x}{5}=\frac{4x-4}{9}#?

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Answer 1 · 2018-03-06T13:52:04

#color(magenta)(x=-10#

#(2x)/5=(4x-4)/9# [Cross multiply]

#9(2x)=5(4x-4)#

#18x=20x-20# [By transposing method]

#20x-18x=-20#

#2x=-20#

#x=-20/2#

#color(magenta)(x=-10#

~Hope this helps! :)