Question

How do you find the x and y intercepts of `6y=3x+6`?

Answer 1

`x`-intercept is `-2` and `y`-intercept is `1`

Explanation:

To find `x`-intercept of any line (actually, I should say any curve) just put `y=0`

and to `x`-intercept of any line (again any curve) just put `x=0`.

Hence `x`-intercept of `6y=3x+6` is given by `6*0=3x+6` or `3x=-6` i.e. `x=-2`

and `y`-intercept of `6y=3x+6` is given by `6y=3*0+6` or `6y=6` i.e. `y=1`.

graph{6y=3x+6 [-2.958, 2.042, -1, 1.5]}