Verify the identity?

#sin(x+y)/cos(x-y)# = #(cot x + cot y) / (1 + cot x cot y)#

1 Answer
Adrone
Mar 7, 2018

Following the explanation.

Explanation:

#sin(x+y)/cos(x-y)# to #(sinxcosy+cosxsiny)/(cosxcosy+sinxsiny)#

#(cotx+coty)/(1+cotxcoty)# to #((cosx/sinx)+(cosy/siny))/(1+(cosxcosy)/(sinxsiny))#
Then from here you could simplify to make it equal to #(sinxcosy+cosxsiny)/(cosxcosy+sinxsiny)#

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