How do you solve # (x-3)/4=2#?

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Answer 1 · 2018-03-07T08:02:01

See a solution process below:

First, multiply each side of the equation by #color(red)(4)# to eliminate the fraction while keeping the equation balanced:

#color(red)(4) xx (x - 3)/4 = color(red)(4) xx 2#

#cancel(color(red)(4)) xx (x - 3)/color(red)(cancel(color(black)(4))) = 8#

#x - 3 = 8#

Now, add #color(red)(3)# to each side of the equation to solve for #x# while keeping the equation balanced:

#x - 3 + color(red)(3) = 8 + color(red)(3)#

#x - 0 = 11#

#x = 11#