How do you factor #49p³q - 36pq³#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Binayaka C. Mar 7, 2018 #pq(7p+6q)(7p-6q)# Explanation: #49p^3q-36pq^3 =pq(49p^2-36q^2)# #=pq((7p)^2-(6q)^2) # #=pq(7p+6q)(7p-6q) ;[a^2-b^2= (a+b)(a-b)]# #=pq(7p+6q)(7p-6q)# [Ans] Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 5344 views around the world You can reuse this answer Creative Commons License