How do you find the derivative of the function: y = arcsin(5x)?

1 Answer
Mar 7, 2018

y' = 5/(1-25x^2)

Explanation:

Just a simple application of the chain rule which states that
d/dx f(g(x)) = f'(g(x))*g'(x)

where f(x) = arcsin(x)
and g(x) = 5x

recall that the derivative of arcsin(x) is 1/(1-x^2) and of 5x is 5

therefore,

the entire derivative is
1/(1-(5x)^2) * 5
=
which is equal to

= 5/(1- 25x^2)